【leetcode题解】【28】【E】Palindrome Number

class Solution(object):
def isPalindrome(self, x):

l = 1
if x < 0 :
return False
#x = 0 - x
while x / (pow(10,l)):
l += 1
#print l

a = 1
b = pow(10,l-1)

for i in range(0,l/2):
#print i,l-i-1
if x/a%10 == x/b%10:
a *= 10
b /= 10
continue
else:
return False
return True
"""
:type x: int
:rtype: bool
"""

Determine whether an integer is a palindrome. Do this without extra space.

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求一个数字是不是回文，
采用求幂和取余，按位比较