【Leetcode】Remove Element

题目链接：

题目：

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

思路：

用count记录要删除元素数目。常用操作要熟记。

算法：

public int removeElement(int[] nums, int val) {
int length = nums.length;
int count = 0;
for (int i = 0; i < nums.length; i++) {
if (nums[i] == val) {
count++;
} else {
nums[i - count] = nums[i];
}
}

length = nums.length - count;
return length;
}