Codeforces 600A Extract Numbers 【模拟】

A. Extract Numbers

time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

You are given string s. Let's call word any
largest sequence of consecutive symbols without symbols ',' (comma) and ';'
(semicolon). For example, there are four words in string "aba,123;1a;0":
"aba", "123", "1a",
"0". A word can be empty: for example, the strings=";;"
contains three empty words separated by ';'.

You should find all words in the given string that are nonnegative INTEGER numbers without leading zeroes and build by them new string a.
String a should contain all words that
are numbers separating them by ',' (the order of numbers should remain the same as in the string s).
By all other words you should build string b in
the same way (the order of numbers should remain the same as in the strings).

Here strings "101", "0" are INTEGER numbers, but "01"
and "1.0" are not.

For example, for the string aba,123;1a;0 the string a would
be equal to "123,0" and string b would
be equal to "aba,1a".

Input

The only line of input contains the string s (1 ≤ |s| ≤ 105).
The string contains only symbols '.' (ASCII 46), ',' (ASCII
44), ';' (ASCII 59), digits, lowercase and uppercase latin letters.

Output

Print the string a to the first line and string b to
the second line. Each string should be surrounded by quotes (ASCII 34).

If there are no words that are numbers print dash (ASCII 45) on the first line. If all words are
numbers print dash on the second line.

Sample test(s)

input

aba,123;1a;0

output

"123,0"
"aba,1a"

input

1;;01,a0,

output

"1"
",01,a0,"

input

1

output

"1"
-

input

a

output

-
"a"

Note

In the second example the string s contains five words: "1",
"", "01", "a0", "".

好弱。。。WA三次才过。

题意：给定一个字符串，字符';' 和 ','将串分开，每部分是一个单词，若出现中间为空的情况（连续两个分隔符），则认为中间的单词是空格。若单词是整数（不能有前导0），则放在串a里面，反之放在串b里面。在a，b串中，单词用','分开。若无单词是整数，a串为"-"，若无单词是非整数，b串为"-"。最后输出a串和b串，如a串（b串）不是"-"，输出时用""括起。

先填上空格，直接模拟就可以了。

AC代码：

#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstdlib>
#include <algorithm>
#include <queue>
#include <stack>
#include <map>
#include <vector>
#define INF 0x3f3f3f
#define eps 1e-8
#define MAXN (100000+10)
#define MAXM (100000)
#define Ri(a) scanf("%d", &a)
#define Rl(a) scanf("%lld", &a)
#define Rf(a) scanf("%lf", &a)
#define Rs(a) scanf("%s", a)
#define Pi(a) printf("%d\n", (a))
#define Pf(a) printf("%.2lf\n", (a))
#define Pl(a) printf("%lld\n", (a))
#define Ps(a) printf("%s\n", (a))
#define W(a) while(a--)
#define CLR(a, b) memset(a, (b), sizeof(a))
#define MOD 1000000007
#define LL long long
#define lson o<<1, l, mid
#define rson o<<1|1, mid+1, r
#define ll o<<1#define rr o<<1|1using namespace std;
char s[MAXN], str[MAXN*2];
char a[MAXN*2], b[MAXN*2];
bool judge(char op){
return op != ',' && op != ';';
}
bool check(char op){
return (op >= 'a' && op <= 'z') || (op >= 'A' && op <= 'Z') || (op == ' ') || (op == '.');
}
int main()
{
while(scanf("%s", s) != EOF)
{
int len = strlen(s), l;
if(len == 1 && (s[0] == ';' || s[0] == ','))
{
printf("-\n");
printf("%c,%c\n", 34, 34);
continue;
}
int top = 0;
for(int i = 0; i < len; i++)
{
if(i == 0)
{
if(s[i] == ',' || s[i] == ';')
{
str[top++] = ' ';
str[top++] = s[i];
if(s[i+1] == ',' || s[i+1] == ';')
str[top++] = ' ';
}
else
str[top++] = s[i];
}
else if(i == len-1)
{
if(s[i] == ',' || s[i] == ';')
{
str[top++] = s[i];
str[top++] = ' ';
}
else
str[top++] = s[i];
}
else
{
if((s[i] == ',' || s[i] == ';') && (s[i+1] == ',' || s[i+1] == ';'))
{
str[top++] = s[i];
str[top++] = ' ';
}
else
str[top++] = s[i];
}
}
str[top] = '\0';
a[0] = b[0]= '"'; a[1] = b[1] = '\0';
int timea = 0, timeb = 0;
for(int i = 0; i < top; )
{
if(judge(str[i]))
{
int j = i; int k = 0; bool flag = true;
while(j < top && judge(str[j]))
{
if(check(str[j]))
flag = false;
s[k++] = str[j++];
}
s[k] = '\0';
if(s[0] == '0' && k > 1)
flag = false;
if(flag)
{
if(timea)
{
l = strlen(a);
a[l] = ',';
a[l+1] = '\0';
}
if(s[0] != ' ')
strcat(a, s);
timea++;
}
else
{
if(timeb)
{
l = strlen(b);
b[l] = ',';
b[l+1] = '\0';
}
if(s[0] != ' ')
strcat(b, s);
timeb++;
}
i = j+1;
}
}
if(timea == 0)
printf("-\n");
else
{
printf("%s", a);
printf("%c\n", 34);
}
if(timeb == 0)
printf("-\n");
else
{
printf("%s", b);
printf("%c\n", 34);
}
}
return 0;
}