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HDU 2896 病毒侵袭(ac自动机)

2015-11-29 00:08 393 查看
题意:

求多模式串匹配,并且输出每个母串中出现的模式串编号,以及所有模式串出现的总次数

分析:

再开个数组记录下id就好啦,然后trie是128叉的

代码:

//
//  Created by TaoSama on 2015-11-27
//  Copyright (c) 2015 TaoSama. All rights reserved.
//
//#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <algorithm>
#include <cctype>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <string>
#include <set>
#include <vector>

using namespace std;
#define pr(x) cout << #x << " = " << x << "  "
#define prln(x) cout << #x << " = " << x << endl
const int N = 1e5 + 10, INF = 0x3f3f3f3f, MOD = 1e9 + 7;
const int M = 500 * 200 + 10, S = 128;

struct AcAutomata {
int root, sz;
int nxt[M][S], fail[M], id[M];
int newNode() {
id[sz] = -1;
memset(nxt[sz], -1, sizeof nxt[sz]);
return sz++;
}
void init() {
sz = 0;
root = newNode();
}
void insert(char *s, int x) {
int n = strlen(s);
int u = root;
for(int i = 0; i < n; ++i) {
int &v = nxt[u][s[i]];
if(v == -1) v = newNode();
u = v;
}
id[u] = x;
}
void build() {
queue<int> q;
fail[root] = root;
for(int i = 0; i < S; ++i) {
int &v = nxt[root][i];
if(~v) {
fail[v] = root;
q.push(v);
} else v = root;
}
while(q.size()) {
int u = q.front(); q.pop();
for(int i = 0; i < S; ++i) {
int &v = nxt[u][i];
if(~v) {
fail[v] = nxt[fail[u]][i];
q.push(v);
} else v = nxt[fail[u]][i];
}
}
}
bool query(char *s, int x) {
int n = strlen(s);
int u = root, ok = false;
vector<int> ans;
for(int i = 0; i < n; ++i) {
u = nxt[u][s[i]];
for(int v = u; v != root; v = fail[v]) {
if(~id[v]) {
ok = true;
ans.push_back(id[v]);
}
}
}
if(!ok) return false;
printf("web %d: ", x);
sort(ans.begin(), ans.end());
for(int i = 0; i < ans.size(); ++i)
printf("%d%c", ans[i], " \n"[i == ans.size() - 1]);
return true;
}
} ac;

int n, q;
char s
;

int main() {
#ifdef LOCAL
freopen("C:\\Users\\TaoSama\\Desktop\\in.txt", "r", stdin);
//  freopen("C:\\Users\\TaoSama\\Desktop\\out.txt","w",stdout);
#endif
ios_base::sync_with_stdio(0);

while(scanf("%d", &n) == 1) {
ac.init();
for(int i = 1; i <= n; ++i) {
char buf[205]; scanf("%s", buf);
ac.insert(buf, i);
}
ac.build();
scanf("%d", &q);
int ans = 0;
for(int i = 1; i <= q; ++i) {
scanf("%s", s);
ans += ac.query(s, i);
}
printf("total: %d\n", ans);
}
return 0;
}
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标签:  ac自动机