hdu 2602 Bone Collector
2015-11-27 19:59
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Bone Collector
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 42169 Accepted Submission(s): 17538
[align=left]Problem Description[/align]
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the
maximum of the total value the bone collector can get ?
[align=left]Input[/align]
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third
line contain N integers representing the volume of each bone.
[align=left]Output[/align]
One integer per line representing the maximum of the total value (this number will be less than 231).
[align=left]Sample Input[/align]
1
5 10
1 2 3 4 5
5 4 3 2 1
[align=left]Sample Output[/align]
14
#include<stdio.h> #include<string.h> #define max(a,b) (a)>(b)?(a):(b) int main() { int T; scanf("%d",&T); while(T--) { int i,j,n,volume; int v[1010],w[1010],dp[1010]; memset(dp,0,sizeof(dp)); scanf("%d%d",&n,&volume); for(i=0;i<n;i++) scanf("%d",&v[i]); for(i=0;i<n;i++) scanf("%d",&w[i]); for(i=0;i<n;i++) for(j=volume;j>=w[i];j--) dp[j]=max(dp[j-w[i]]+v[i],dp[j]); printf("%d\n",dp[volume]); } return 0; }
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