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[LeetCode243]Shortest Word Distance

2015-11-24 06:40 423 查看
Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list.

For example,
Assume that words = ["practice", "makes", "perfect", "coding", "makes"].

Given word1 = “coding”, word2 = “practice”, return 3.
Given word1 = "makes", word2 = "coding", return 1.

Note:
You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.

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这道题之所以easy是因为它的note帮我们排除了很多乱七八糟的东西, 所以用两个pointer遍历一遍list即可。

class Solution {
public:
int shortestDistance(vector<string>& words, string word1, string word2) {
int pos1 = -1, pos2 = -1, minLen = INT_MAX;
for(int i = 0; i<words.size(); ++i){
if(words[i] == word1) pos1 = i;
else if(words[i] == word2) pos2 = i;
if(pos1 != pos2 && pos1!=-1 && pos2 != -1) minLen = min(abs(pos1-pos2), minLen);
}
return minLen;
}
};
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标签:  leetcode