Codeforces Round #332 (Div. 2)_B. Spongebob and Joke
2015-11-21 04:02
453 查看
B. Spongebob and Joke
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output
While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence a1, a2, ..., am of
length m, consisting of integers from 1 to n,
not necessarily distinct. Then he picked some sequence f1, f2, ..., fn of
length n and for each number ai got
number bi = fai.
To finish the prank he erased the initial sequence ai.
It's hard to express how sad Patrick was when he returned home from shopping! We will just say that Spongebob immediately got really sorry about what he has done and he is now trying to restore the original sequence. Help him do this or determine that this
is impossible.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 100 000) —
the lengths of sequences fi and bi respectively.
The second line contains n integers, determining sequence f1, f2, ..., fn (1 ≤ fi ≤ n).
The last line contains m integers, determining sequence b1, b2, ..., bm (1 ≤ bi ≤ n).
Output
Print "Possible" if there is exactly one sequence ai,
such that bi = fai for
all i from 1 to m.
Then print m integers a1, a2, ..., am.
If there are multiple suitable sequences ai,
print "Ambiguity".
If Spongebob has made a mistake in his calculations and no suitable sequence ai exists,
print "Impossible".
Sample test(s)
input
output
input
output
input
output
Note
In the first sample 3 is replaced by 1 and
vice versa, while 2 never changes. The answer exists and is unique.
In the second sample all numbers are replaced by 1, so it is impossible to unambiguously restore the original sequence.
In the third sample fi ≠ 3 for
all i, so no sequence ai transforms
into such bi and
we can say for sure that Spongebob has made a mistake.
用哈希过的
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output
While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence a1, a2, ..., am of
length m, consisting of integers from 1 to n,
not necessarily distinct. Then he picked some sequence f1, f2, ..., fn of
length n and for each number ai got
number bi = fai.
To finish the prank he erased the initial sequence ai.
It's hard to express how sad Patrick was when he returned home from shopping! We will just say that Spongebob immediately got really sorry about what he has done and he is now trying to restore the original sequence. Help him do this or determine that this
is impossible.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 100 000) —
the lengths of sequences fi and bi respectively.
The second line contains n integers, determining sequence f1, f2, ..., fn (1 ≤ fi ≤ n).
The last line contains m integers, determining sequence b1, b2, ..., bm (1 ≤ bi ≤ n).
Output
Print "Possible" if there is exactly one sequence ai,
such that bi = fai for
all i from 1 to m.
Then print m integers a1, a2, ..., am.
If there are multiple suitable sequences ai,
print "Ambiguity".
If Spongebob has made a mistake in his calculations and no suitable sequence ai exists,
print "Impossible".
Sample test(s)
input
3 3 3 2 1 1 2 3
output
Possible 3 2 1
input
3 3 1 1 1 1 1 1
output
Ambiguity
input
3 3 1 2 1 3 3 3
output
Impossible
Note
In the first sample 3 is replaced by 1 and
vice versa, while 2 never changes. The answer exists and is unique.
In the second sample all numbers are replaced by 1, so it is impossible to unambiguously restore the original sequence.
In the third sample fi ≠ 3 for
all i, so no sequence ai transforms
into such bi and
we can say for sure that Spongebob has made a mistake.
用哈希过的
#include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <algorithm> using namespace std; const int max1 = 101000; struct node { int x, y; }a[max1]; int b[max1]; int f[max1]; int a1[max1]; int main() { memset(f, 0, sizeof(f)); memset(a, 0, sizeof(a)); memset(a1, 0, sizeof(a1)); memset(b, 0, sizeof(b)); for (int i = 0; i<max1; i++) a[i].x = 0; int n, m; cin >> n>> m; for (int i = 1; i<=n; i++) { cin >> f[i]; a[f[i]].x ++ ; a[f[i]].y = i; } for (int i = 1; i<=m; i++) cin >> b[i]; int flag1 = 0; int flag = 0; int num = 1; for (int i = 1; i<=m; i++) { if (a[b[i]].x == 1) { a1[num++] = a[b[i]].y; } else if (a[b[i]].x >= 2) { a1[num++] = a[b[i]].y; flag = 1; } else if (a[b[i]].x == 0) { flag = 2; break; } } if (flag == 2) cout << "Impossible" << endl; else if (flag == 1) cout << "Ambiguity" << endl; else { cout << "Possible" << endl; for (int i = 1; i<num-1; i++) cout << a1[i] << " " ; cout << a1[num-1] << endl; } return 0; }
相关文章推荐
- java.lang.NoClassDefFoundError: Failed resolution of: Landroid/support/v4/util/LruCache;
- UVA - 220 Othello(黑白棋)
- 214. Shortest Palindrome
- python冒泡算法,lambda表达式
- R语言初识#02
- vim 实际行跟屏幕行移动命令
- PHPCMS V9 使str_cut可以输出html源代码
- codeforces #332 div 2 C. Day at the Beach
- codeforces #332 div 2 B. Spongebob and Joke
- Codeforces #332 D. Spongebob and Squares (公式)
- codeforces #332 div 2 A. Patrick and Shopping
- Windows Server2012 配置打印服务器图文教程
- 南理OJ_The Triangle
- Windows Server2012 配置打印服务器图文教程
- Codeforces #332 C. Day at the Beach (贪心)
- excel导入 服务器忘了装组件了。。。
- 多表关联小记
- Codeforces Round #332 (Div. 2) D. Spongebob and Squares 数学题枚举
- Codeforces #332 B. Spongebob and Joke (思路)
- getRequestDispatcher()与sendRedirect()的区别