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搜索时的建议输入

2015-11-20 20:01 417 查看
文件1:ajax_gethint.html

<!DOCTYPE html PUBLIC>
<!--[if IE 7]>         <html class="no-js ie7"> <![endif]-->
<!--[if IE 8]>         <html class="no-js ie8"> <![endif]-->
<!--[if IE 9]>         <html class="no-js ie9"> <![endif]-->
<!--[if gt IE 9]><!--> <html class="no-js"> <!--<![endif]-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script type="text/javascript">
function showHint(str)
{
var xmlhttp;
if (str.length==0)
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","gethint.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>

<h3>请在下面的输入框中键入字母(A - Z):</h3>
<form action="">
姓氏:<input type="text" id="txt1" onkeyup="showHint(this.value)" />
</form>
<p>建议:<span id="txtHint"></span></p>

</body>
</html>


文件2:   gethint.php

 

<?php
// 用名字来填充数组
$a[]="Anna";
$a[]="Brittany";
$a[]="Cinderella";
$a[]="Diana";
$a[]="Eva";
$a[]="Fiona";
$a[]="Gunda";
$a[]="Hege";
$a[]="Inga";
$a[]="Johanna";
$a[]="Kitty";
$a[]="Linda";
$a[]="Nina";
$a[]="Ophelia";
$a[]="Petunia";
$a[]="Amanda";
$a[]="Raquel";
$a[]="Cindy";
$a[]="Doris";
$a[]="Eve";
$a[]="Evita";
$a[]="Sunniva";
$a[]="Tove";
$a[]="Unni";
$a[]="Violet";
$a[]="Liza";
$a[]="Elizabeth";
$a[]="Ellen";
$a[]="Wenche";
$a[]="Vicky";

//获得来自 URL 的 q 参数
$q=$_GET["q"];

//如果 q 大于 0,则查找数组中的所有提示
if (strlen($q) > 0)
{
$hint="";
for($i=0; $i<count($a); $i++)
{
if (strtolower($q)==strtolower(substr($a[$i],0,strlen($q))))
{
if ($hint=="")
{
$hint=$a[$i];
}
else
{
$hint=$hint." , ".$a[$i];
}
}
}
}

// 如果未找到提示,则把输出设置为 "no suggestion"
// 否则设置为正确的值
if ($hint == "")
{
$response="no suggestion";
}
else
{
$response=$hint;
}

//输出响应
echo $response;
?>


效果:
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