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[LeetCode]95. Implement Stack using Queues用队列实现栈

2015-11-19 11:26 519 查看
Implement the following operations of a stack using queues.

push(x) -- Push element x onto stack.

pop() -- Removes the element on top of the stack.

top() -- Get the top element.

empty() -- Return whether the stack is empty.

Notes:

You must use only standard operations of a queue -- which means only
push to back
,
peek/pop from front
,
size
, and
is empty
operations are valid.

Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.

You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

Update (2015-06-11):
The class name of the Java function had been updated to MyStack instead of Stack.

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and all test cases.

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解法1:和题目Implement Queue using Stacks用栈实现队列相似,本题反过来用队列实现栈。方法相同,使用两个队列。需要注意的一点是,在top()操作中,不论是对哪一个队列操作,在取得队尾元素后都还需要将这个队尾元素移到另一个队列中,以保持顺序一致。

class Stack {
public:
// Push element x onto stack.
void push(int x) {
while (!q2.empty()) {
q1.push(q2.front());
q2.pop();
}
q1.push(x);
}
// Removes the element on top of the stack.
void pop() {
if (!q1.empty()) {
while (q1.size() > 1) {
q2.push(q1.front());
q1.pop();
}
q1.pop();
}
else {
while (q2.size() > 1) {
q1.push(q2.front());
q2.pop();
}
q2.pop();
}
}
// Get the top element.
int top() {
if (!q1.empty()) {
while (q1.size() > 1) {
q2.push(q1.front());
q1.pop();
}
int ret = q1.front();
q2.push(ret); // 注意必须将这个top也移到另一个队列
q1.pop();
return ret;
}
else {
while (q2.size() > 1) {
q1.push(q2.front());
q2.pop();
}
int ret = q2.front();
q1.push(ret); // 注意必须将这个top也移到另一个队列
q2.pop();
return ret;
}
}
// Return whether the stack is empty.
bool empty() {
return q1.empty() && q2.empty();
}
private:
std::queue<int> q1, q2;
};


解法2:同样使用一个队列q就可以搞定。在push()操作的时候,只要队列q中有元素,我们先将这些以前的元素搬到另一个队列tmp中暂存起来,然后再push当前元素到队列q中,最后将缓存队列tmp中的所有元素又搬回到q中来。这样最先进入队列的元素恰好要在最后才能取出来的。

class Stack {
public:
// Push element x onto stack.
void push(int x) {
std::queue<int> tmp;
while (!q.empty()) {
tmp.push(q.front());
q.pop();
}
q.push(x);
while (!tmp.empty()) {
q.push(tmp.front());
tmp.pop();
}
}
// Removes the element on top of the stack.
void pop() {
q.pop();
}
// Get the top element.
int top() {
return q.front();
}
// Return whether the stack is empty.
bool empty() {
return q.empty();
}
private:
std::queue<int> q;
};
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