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[PTA]Week8 Sort Three Distinct Keys

2015-11-15 10:28 253 查看

  看了很久题目也没看懂啥意思,莫名其妙就过了,我猜这大概是传说中桶排序 → →


  
#include <stdio.h>
#include <stdlib.h>

typedef enum { true, false, maybe } Keys;
typedef Keys ElementType;

void Read( ElementType A[], int N ); /* details omitted */

void MySort( ElementType A[], int N );

void PrintA( ElementType A[], int N )
{
int i, k;

k = i = 0;
for ( ; i<N && A[i]==false; i++ );
if ( i > k )
printf("false in A[%d]-A[%d]\n", k, i-1);
k = i;
for ( ; i<N && A[i]==maybe; i++ );
if ( i > k )
printf("maybe in A[%d]-A[%d]\n", k, i-1);
k = i;
for ( ; i<N && A[i]==true; i++ );
if ( i > k )
printf("true in A[%d]-A[%d]\n", k, i-1);
if ( i < N )
printf("Wrong Answer\n");
}

int main()
{
int N;
ElementType *A;

scanf("%d", &N);
A = (ElementType *)malloc(N * sizeof(ElementType));
Read( A, N );
MySort( A, N );
PrintA( A, N );
return 0;
/* Your function will be put here */
}

void Read( ElementType A[], int N )
{
int i;
for(i=0;i<N;i++){
scanf("%d",&A[i]);
}
return;
}

void MySort( ElementType A[], int N )
{
int i;
int count1,count2,count3;
count1=count2=count3=0;
for(i=0;i<N;i++){
if(A[i]==false){
count1++;
}
else if(A[i]==maybe){
count2++;
}
else if(A[i]==true){
count3++;
}
}
for(i=0;i<count1;i++){
A[i]=false;
}
for(i=count1;i<count1+count2;i++){
A[i]=maybe;
}
for(i=count1+count2;i<N;i++){
A[i]=true;
}
return;
}
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