数值的整数次方

public class OngoingTimesSquare{
public static double Power(double base,int exponent){
if(exponent < 0 ){
exponent = - exponent;
return 1/solve(base,exponent);
}
renturn solve(base,exponent);
}

public double solve(double base, int exponent){
if(exponent==0) return 1;
if(exponent%2==1){
return base*solve(base,(exponent-1)/2)*solve(base,(exponent-1)/2);
}else{
return solve(base,exponent/2)*solve(base,exponent/2);
}
}
}

public double Power(double base, int exponent) {
if(exponent == 0){
return 1;
}else if(exponent > 0){
double num = base;
for(int i = 1; i < exponent; i++){
num = num * base;
}
return num;
}else {
double nums = base;
int flag = -exponent;
for(int i = 1; i < flag; i++){
nums = nums * base;
}
return 1/nums;
}
}
}