lightoj 1203(凸包)
2015-11-07 20:29
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题意:有n个点,问从哪个点用最小的角度可以看到其他所有的点,输出最小角度。
题解:把n个点求凸包,凸包内部的点角度都是360,所以结果就是凸包的最小内角。
题解:把n个点求凸包,凸包内部的点角度都是360,所以结果就是凸包的最小内角。
#include <cstdio> #include <cstring> #include <algorithm> #include <vector> #include <cmath> using namespace std; const double eps = 1e-9; const double PI = acos(-1); double Sqr(double x) { return x * x; } int dcmp(double x) { if (fabs(x) < eps) return 0; return x > 0 ? 1 : -1; } struct Point { double x, y; Point(double a = 0, double b = 0): x(a), y(b) {} }; typedef Point Vector; typedef vector<Point> Polygon; Vector operator + (const Vector& a, const Vector& b) { return Vector(a.x + b.x, a.y + b.y); } Vector operator - (const Vector& a, const Vector& b) { return Vector(a.x - b.x, a.y - b.y); } Vector operator * (const Vector& a, double b) { return Vector(a.x * b, a.y * b); } Vector operator / (const Vector& a, double b) { return Vector(a.x / b, a.y / b); } bool operator == (const Vector& a, const Vector& b) { return !dcmp(a.x - b.x) && !dcmp(a.y - b.y); } bool operator < (const Vector& a, const Vector& b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } double Dot(const Vector& a, const Vector& b) { return a.x * b.x + a.y * b.y; } double Length(const Vector& a) { return sqrt(Dot(a, a)); } double Cross(const Vector& a, const Vector& b) { return a.x * b.y - a.y * b.x; } double Angle(const Vector& a, const Vector& b) { return acos(Dot(a, b) / Length(a) / Length(b)); } double angle(Vector v) { return atan2(v.y, v.y); } int ConvexHull(Point* P, int cnt, Point* res) { sort(P, P + cnt); cnt = unique(P, P + cnt) - P; int m = 0; for (int i = 0; i < cnt; i++) { while (m > 1 && Cross(res[m - 1] - res[m - 2], P[i] - res[m - 2]) <= 0) m--; res[m++] = P[i]; } int k = m; for (int i = cnt - 2; i >= 0; i--) { while (m > k && Cross(res[m - 1] - res[m - 2], P[i] - res[m - 2]) <= 0) m--; res[m++] = P[i]; } if (cnt > 1) m--; return m; } const int N = 1e5 + 5; int n; Point P , res ; int main() { int t, cas = 1; scanf("%d", &t); while (t--) { scanf("%d", &n); for (int i = 0; i < n; i++) scanf("%lf%lf", &P[i].x, &P[i].y); int cnt = ConvexHull(P, n, res); if (cnt < 3) { printf("Case %d: 0\n", cas++); continue; } res[cnt] = res[0]; res[cnt + 1] = res[1]; double ans = 2 * PI; for (int i = 1; i <= cnt; i++) ans = min(ans, Angle(res[i - 1] - res[i], res[i + 1] - res[i])); printf("Case %d: %.10lf\n", cas++, ans * 180 / PI); } return 0; }
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