uva11865

// #pragma comment(linker, "/STACK:1024000000,1024000000")
#include <iostream>
#include <algorithm>
#include <iomanip>
#include <sstream>
#include <string>
#include <stack>
#include <queue>
#include <deque>
#include <vector>
#include <map>
#include <set>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <limits.h>
#define DEBUG
#ifdef DEBUG
#define debug(...) printf( __VA_ARGS__ )
#else
#define debug(...)
#endif
#define MEM(x,y) memset(x, y,sizeof x)
using namespace std;
typedef long long LL;
typedef unsigned long long ULL;
typedef pair<int,int> ii;
const int inf = 1 << 30;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
// int n,m,c;
int t;
const int maxn = 1e4 + 10;
int in[maxn], pre[maxn];
int id[maxn], vis[maxn];
struct Node{
int u,v,cost;
int wide;
bool operator < (const Node& b)const{
return this->wide < b.wide;
}
}E[maxn], tmp[maxn];
int Drected_MST(int root,int n,int m,int wide){
int ret = 0;
// return -1;
memcpy(tmp, E,sizeof tmp);
while(true){
MEM(in,INF);
for (int i = 0;i < m;i++){
int u = tmp[i].u, v = tmp[i].v;
if (tmp[i].cost < in[v] && u != v && tmp[i].wide >= wide){
pre[v] = u;
in[v] = tmp[i].cost;
}
}//连通性的判断
for (int i = 0;i < n;i++){
if (i == root) continue;
if (in[i] == INF) return -1;
}
// debug("####\n");
int cnt = 0;
MEM(id, -1);
MEM(vis, -1);
in[root] = 0;

<span style="white-space:pre">		</span>//环的检测

for (int i = 0;i < n;i++){
ret += in[i];
int v = i;
while(vis[v] != i && id[v] == -1 && v != root){
vis[v] = i;
v = pre[v];
}
if (v != root && id[v] == -1){
for (int u = pre[v];u != v;u = pre[u]){
id[u] = cnt;
}
id[v] = cnt++;//
}
}
if (cnt == 0) break;//无环直接输出答案。
for (int i = 0;i < n;i++){//对独立的点进行标记
if (id[i] == -1){
id[i] = cnt++;
}
}
for (int i = 0;i < m;i++){
int v = tmp[i].v;
tmp[i].u = id[tmp[i].u];
tmp[i].v = id[tmp[i].v];
if (tmp[i].u != tmp[i].v)
tmp[i].cost -= in[v];
}
n = cnt;
root = id[root];
}
return ret;
}
int main()
{
// freopen("in.txt","r",stdin);
// freopen("out.txt","w",stdout);
int n,m,c;
scanf("%d",&t);
while(t--){
scanf("%d%d%d",&n,&m,&c);
int low = INF, high = -INF;
for (int i = 0;i < m;i++){
scanf("%d%d%d%d",&E[i].u,&E[i].v,&E[i].wide,&E[i].cost);
low = min(E[i].wide,low);
high = max(E[i].wide,high);
}
sort(E,E+m);
// debug("high = %d\t,low = %d\n",high,low);
int num = Drected_MST(0,n,m,0);
if (num == -1 || num > c){
puts("streaming not possible.");
continue;
}
while(low <= high){
int mid = (low + high)/2;
int check = Drected_MST(0,n,m,mid);
if (check == -1 || check > c){
high = mid - 1;
}else low = mid + 1;
}
printf("%d kbps\n",high);
}
return 0;
}