您的位置:首页 > 其它

[LeetCode] Search Insert Position

2015-11-05 23:05 246 查看


Search Insert Position

My Submissions

Question

Total Accepted: 79962 Total
Submissions: 222866 Difficulty: Medium

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.

[1,3,5,6]
, 5 → 2

[1,3,5,6]
, 2 → 1

[1,3,5,6]
, 7 → 4

[1,3,5,6]
, 0 → 0

public class Solution {
public int searchInsert(int[] nums, int target) {
if(nums.length<1)return 0;
int head=0;int tail=nums.length-1;
while(head<tail){
int mid=(head+tail)/2;
if(nums[mid]==target){
return mid;
}
else{
if(head<tail&&nums[mid]>target){
tail=mid-1;
}
else{
if(nums[mid]<target){
head=mid+1;
}
}
}

}
if(nums[head]>=target){
return head;
}
else{
return head+1;
}
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: