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POJ 2752 Seek the Name, Seek the Fame (kmp)

2015-10-29 21:57 381 查看
题意:

求串所有前缀和后缀的lcp(最长公共前缀)

分析:

就是nxt[i]的含义,别忘记算上n就好了

代码:

//
//  Created by TaoSama on 2015-10-28
//  Copyright (c) 2015 TaoSama. All rights reserved.
//
//#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <algorithm>
#include <cctype>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <string>
#include <set>
#include <vector>

using namespace std;
#define pr(x) cout << #x << " = " << x << "  "
#define prln(x) cout << #x << " = " << x << endl
const int N = 4e5 + 10, INF = 0x3f3f3f3f, MOD = 1e9 + 7;

int n, nxt
;
char s
;

void getNxt() {
nxt[0] = -1;
int i = 0, j = -1;
while(i < n) {
if(j == -1 || s[i] == s[j]) nxt[++i] = ++j;
else j = nxt[j];
}
}

int main() {
#ifdef LOCAL
freopen("C:\\Users\\TaoSama\\Desktop\\in.txt", "r", stdin);
//  freopen("C:\\Users\\TaoSama\\Desktop\\out.txt","w",stdout);
#endif
ios_base::sync_with_stdio(0);

while(scanf("%s", s) == 1) {
n = strlen(s);
getNxt();
vector<int> ans;
for(int i = nxt
; i; i = nxt[i]) ans.push_back(i);
sort(ans.begin(), ans.end());
for(int i = 0; i < ans.size(); ++i) printf("%d ", ans[i]);
printf("%d\n", n);
}
return 0;
}
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标签:  kmp