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hdu 1427 速算24点

2015-10-20 17:25 253 查看
原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1427

参照<<编程之美>>上的写法,时间卡的挺紧的,用cin tle scanf过了/(ㄒoㄒ)/~~

#include<algorithm>
#include<iostream>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<vector>
#include<string>
#include<map>
using std::map;
using std::fabs;
using std::pair;
using std::swap;
using std::string;
using std::next_permutation;
#define pb(e) push_back(e)
#define sz(c) (int)(c).size()
#define mp(a, b) make_pair(a, b)
#define all(c) (c).begin(), (c).end()
#define iter(c) decltype((c).begin())
#define cls(arr, val) memset(arr, val, sizeof(arr))
#define cpresent(c, e) (find(all(c), (e)) != (c).end())
#define rep(i, n) for(int i = 0; i < (int)n; i++)
#define tr(c, i) for(iter(c) i = (c).begin(); i != (c).end(); ++i)
const int N = 20;
const double eps = 1E-7;
const int INF = 0x3f3f3f3f;
typedef unsigned long long ull;
int arr[4];
char ret[4][10];
map<string, int> A;
bool dfs(int n) {
if (1 == n) {
return arr[0] == 24;
}
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
int a = arr[i], b = arr[j];
arr[j] = arr[n - 1];
arr[i] = a + b;
if (dfs(n - 1)) return true;
arr[i] = a - b;
if (dfs(n - 1)) return true;
arr[i] = b - a;
if (dfs(n - 1)) return true;
arr[i] = a * b;
if (dfs(n - 1)) return true;
if (b != 0 && 0 == a % b) {
arr[i] = a / b;
if (dfs(n - 1)) return true;
}
if (a != 0 && 0 == b % a) {
arr[i] = b / a;
if (dfs(n - 1)) return true;
}
arr[i] = a;
arr[j] = b;
}
}
return false;
}
void init() {
A["A"] = 1;
A["2"] = 2;
A["3"] = 3;
A["4"] = 4;
A["5"] = 5;
A["6"] = 6;
A["7"] = 7;
A["8"] = 8;
A["9"] = 9;
A["10"] = 10;
A["J"] = 11;
A["Q"] = 12;
A["K"] = 13;
}
bool solve() {
for (int i = 0; i < 4; i++) {
arr[i] = A[ret[i]];
}
do {
if (dfs(4)) return true;
} while (next_permutation(arr, arr + 4));
return false;
}
int main() {
#ifdef LOCAL
freopen("in.txt", "r", stdin);
freopen("out.txt", "w+", stdout);
#endif
init();
while (~scanf("%s %s %s %s", ret[0], ret[1], ret[2], ret[3])) {
puts(solve() ? "Yes" : "No");
}
return 0;
}
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