您的位置:首页 > 产品设计 > UI/UE

Request

2015-10-18 16:01 435 查看
一、Request 通过表单收集客户机数据

input的type属性:text,checkbox,hidden,password,radio,file.

<form action="/day9/servlet/requestDemo2" method="post">
 用户名:<input type="text" name="username"/><br/>
   密码:<input type="password" name="password"><br/>
   性别:<input type="radio" name="gender" value="male">男
     <input type="radio" name="gender" value="female">女<br/>
   所在地:<select name="location">
<option value="shanghai">上海</option>
<option value="henan">河南</option>
<option value="beijing">北京</option>
</select><br/>
  爱好:<input type="checkbox" name="likes" value="sing">唱歌
   <input type="checkbox" name="likes" value="tiaowu">跳舞
  <input type="checkbox" name="likes" value="paobu">跑步
  <input type="checkbox" name="likes" value="dushu">读书<br/>
   备注:<textarea row="3" row="60" name="description" ></textarea><br/>
  大头贴:<input type="file" name="imapge" ><br/>
  <input type="hidden" name="id" value="890">
  <input type="submit" value="提交">
</form>


Java:

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
System.out.println(request.getParameter("username"));
System.out.println(request.getParameter("password"));
System.out.println(request.getParameter("gender"));
System.out.println(request.getParameter("location"));
String    likes[]=request.getParameterValues("likes");
for(int i=0;likes!=null&&i<likes.length;i++){
System.out.println(likes[i]);
}
System.out.println(request.getParameter("description"));
System.out.println(request.getParameter("id"));

}


二、request乱码问题

//get 方式乱发解决问题
private void test1(HttpServletRequest request) throws UnsupportedEncodingException{
String username=request.getParameter("username");
username=new String(username.getBytes("iso8859-1"),"UTF-8");
System.out.println(username);
}
//post 方式乱码解决问题
private void test2(HttpServletRequest request) throws UnsupportedEncodingException{
request.setCharacterEncoding("UTF-8");
String username=request.getParameter("username");
System.out.println(username);
}


三、request请求转发

请求转发的特点:

客户端只发送一次请求,而服务器段有多个资源调用

客户端浏览器地址栏没有变化

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String data="aaa";
request.setAttribute("data", data);
request.getRequestDispatcher("/test.jsp").forward(request, response);

}


如果在调用forward方法之前,在Servlet程序中写入的部分内容已经被真正地传送到了客户端,forward方法将抛出IllegalStateException异常。

String data = "rsl";
PrintWriter writer = response.getWriter();
writer.write(data);
writer.close();
request.getRequestDispatcher("/index.jsp").forward(request, response);


多个转发,一定要记得转发一个,return;

String data = "rsl";
if(true){
request.getRequestDispatcher("/index.jsp").forward(request, response);
return ;//解决只要加个return就可以
}
request.getRequestDispatcher("/index.jsp").forward(request, response);


如果在调用forward方法之前向Servlet引擎的缓冲区中写入了内容,只要写入到缓冲区中的内容还没有被真正输出到客户端,forward方法就可以被正常执行,原来写入到输出缓冲区中的内容将被清空,但是,已写入到HttpServletResponse对象中的响应头字段信息保持有效。forward的细节:forward时,会清空reponse中的数据;

String data = "rsl";
PrintWriter writer = response.getWriter();
writer.write(data);
request.getRequestDispatcher("/index.jsp").forward(request, response);


index.jsp 页面 并看不到 rs1.
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: