c总结2 ---自己实现字符串的拷贝(指针学习1)

int _tmain(int argc, _TCHAR* argv[])
{
char * p1 = "abcde";

printf("*p1++ = %c \n", *p1++ );  //a   ++在后  想当于 先将*p的值进行打印  然后*p+1
printf("*p1++ = %c \n", *p1++);   //b
printf("*p1++ = %c \n", *p1++);   //c

system("pause");
return 0;
}

#include "stdafx.h"
#include <stdlib.h>
#include <string.h>

void myCopy(char *from, char* to)
{
//当*from为 '\0'的时候结束   每次执行语句后 *from *to自增 将指针加1
for ( ; *from != '\0'; *from++, *to++)
{
//将 *from的值赋值给*to
*to = *from;
}

//因为是字符指针 要使用'\0'结束
*to = '\0';
}

int _tmain(int argc, _TCHAR* argv[])
{
char * p1 = "abcde";
char p2[9];	//定义一个数组用来封装拷贝的数据

myCopy(p1, p2);
printf("p2 = %s \n", p2);
system("pause");
return 0;
}