1002. A+B for Polynomials (25)

1002. A+B for Polynomials (25)

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi
(i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input

2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output

3 2 1.5 1 2.9 0 3.2

#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <string>
#include <vector>
#include <map>
using namespace std ;

#define N 1001

double rs
;

int main()
{
//freopen("in.txt","r",stdin);
int n ;
int i , xi ;
double zhi ;
scanf("%d",&n);
for(i = 0 ; i < n ; i ++)
{
scanf("%d%lf",&xi , &zhi) ;
rs[xi] += zhi ;
}
scanf("%d",&n);
for(i = 0 ; i < n ; i ++)
{
scanf("%d%lf",&xi , &zhi) ;
rs[xi] += zhi ;
}
int len = 0 ;
vector<int> v ;
for(i = 1000 ; i >= 0 ; i--)
{
if(rs[i] != 0 ){
v.push_back(i) ;
len ++ ;
}
}
printf("%d",len) ;
for(i = 0 ; i< len ; i++)
{
printf(" %d %.1lf" , v[i] , rs[v[i]]);
}
printf("\n");
return 0 ;
}

#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <string>
#include <vector>
#include <map>
#include <iterator>
using namespace std ;

#define N 1001

map<int , double> mp ;

struct data{
int xi ;
double zhi ;
};

int main()
{
// freopen("in.txt","r",stdin);
int n ;
int i , xi ;
double zhi ;
scanf("%d",&n);
for(i = 0 ; i < n ; i ++)
{
scanf("%d%lf",&xi , &zhi) ;
mp[xi] += zhi ;
}
scanf("%d",&n);
for(i = 0 ; i < n ; i ++)
{
scanf("%d%lf",&xi , &zhi) ;
mp[xi] += zhi ;
}

int len = 0 ;
data dt ;
vector<data> v ;
map<int ,double>::iterator  it ;
for(it = mp.begin() ; it != mp.end() ; ++it)
{
dt.xi = it->first;
dt.zhi =  it->second ;
if(dt.zhi != 0)
{
v.push_back(dt) ;
len ++ ;
}
}
printf("%d",len) ;
for(i = len-1 ; i >= 0 ; i--)
{
printf(" %d %.1lf" , v[i].xi , v[i].zhi);
}
printf("\n");
return 0 ;
}