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2015-10-15 08:57 323 查看

1.使用@Expose可以区分实体中不想被序列化的属性

@Expose标签的2个属性.



1.1 deserialize

(boolean) 反序列化默认 true
1.2

serialize

(boolean) 序列化默认 true

使用 new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create();创建Gson对象，没有@Expose注释的属性将不会被序列化

[align=left] [/align]

public class User {

@Expose

private String username;

@Expose(serialize=false)

private int age ;

private List<String> list;

public User(String username, int age) {

super();

this.username = username;

this.age = age;

}

public String getUsername() {

return username;

}

public void setUsername(String username) {

this.username = username;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public List<String> getList() {

return list;

}

public void setList(List<String> list) {

this.list = list;

}

public static void main(String []args){

User user = new User("lemon",27);

List<String> list = new ArrayList<String>();

list.add("l1");

list.add("l2");

user.setList(list);

Gson g1 = new Gson();

//使用 new Gson();

System.out.println(g1.toJson(user)); //{"username":"lemon","age":27,"list":["l1","l2"]}

//使用 new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

Gson g2 = new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

System.out.println(g2.toJson(user)); //{"username":"lemon"}

}

}

2.使用@SerializedName标签定义属性序列化后的名字

@Expose

@SerializedName("name")

private String username;

public static void main(String []args){

User user = new User("lemon",27);

List<String> list = new ArrayList<String>();

list.add("l1");

list.add("l2");

user.setList(list);

Gson g1 = new Gson();

//使用 new Gson();

//{"name":"lemon","age":27,"list":["l1","l2"]}

System.out.println(g1.toJson(user));

//使用 new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

Gson g2 = new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

//{"name":"lemon"}

System.out.println(g2.toJson(user));

}

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