您的位置:首页 > 其它

LeetCode——Jump Game

2015-10-14 21:59 471 查看
Description:

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

For example:
A =
[2,3,1,1,4]
, return
true
.

A =
[3,2,1,0,4]
, return
false
.

贪心,每次取最大step看是否能够到达最后的索引。

public class Solution {
public boolean canJump(int[] nums) {
if(nums.length == 0 || nums.length == 1) return true;

int maxStep = nums[0];
for(int i=0; i<nums.length; i++) {

if(maxStep == 0) {
return false;
}

maxStep = Math.max(maxStep-1, nums[i]);

if(maxStep+i >= nums.length-1) {
return true;
}
}
return true;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: