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UVa 10881.Piotr's Ants【RuijiaLiu随书练习】【10月7】

2015-10-07 13:14 585 查看
Piotr's Ants
蚂蚁碰撞,相当于对穿而过。过一段时间以后蚂蚁的相对位置不变。代码:
#include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn = 10000 + 10;
struct ants {
int id, p, d;
bool operator < (const ants& a) const {
return a.p < p;
}
};
bool cmp (ants a, ants b) {
return a.id < b.id;
}
int main() {
int N, kase = 1;
scanf ("%d", &N);
while (N--) {
int l, t, n;
char dir;
ants before[maxn], after[maxn];
scanf ("%d%d%d", &l, &t, &n);
for (int i = 0; i < n; i++) {
scanf ("%d %c", &before[i].p, &dir);
before[i].id = i;
if (dir == 'R') {
after[i].p = before[i].p + t;
after[i].d = 1;
} else {
after[i].p = before[i].p - t;
after[i].d = -1;
}
}
sort (before, before + n);
sort (after, after + n);
for (int i = 0; i < n; i++) {
after[i].id = before[i].id;
if (i < n - 1 && after[i].p == after[i + 1].p)
after[i].d = after[i + 1].d = 0;
}
sort (after, after + n, cmp);
printf ("Case #%d:\n", kase++);
for (int i = 0; i < n; i++) {
if (after[i].p < 0 || after[i].p > l) printf ("Fell off\n");
else if (after[i].d == 1) printf ("%d R\n", after[i].p);
else if (after[i].d == -1) printf ("%d L\n", after[i].p);
else printf ("%d Turning\n", after[i].p);
}
printf("\n");
}
return 0;
}
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