CodeForces 415B Mashmokh and Tokens

链接：http://codeforces.com/problemset/problem/415/B

Mashmokh and Tokens

time limit per test：1 second

memory limit per test：256 megabytes

input：standard input

output：standard output

Bimokh is Mashmokh's boss. For the following n days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker
can give some of his tokens back to get a certain amount of money. The worker can save the rest of tokens but he can't use it in any other day to get more money. If a worker gives back
w tokens then he'll get

 dollars.

Mashmokh likes the tokens however he likes money more. That's why he wants to save as many tokens as possible so that the amount of money he gets is maximal possible each day. He has
n numbers x1, x2, ..., xn. Number
xi is the number of tokens given to each worker on the
i-th day. Help him calculate for each of
n days the number of tokens he can save.

Input

The first line of input contains three space-separated integers
n, a, b (1 ≤ n ≤ 105; 1 ≤ a, b ≤ 109). The second line of input contains
n space-separated integers
x1, x2, ..., xn (1 ≤ xi ≤ 109).

Output

Output n space-separated integers. The
i-th of them is the number of tokens Mashmokh can save on the
i-th day.

Sample test(s)

Input

5 1 4
12 6 11 9 1

Output

02 3 1 1

Input

3 1 2
1 2 3

Output

1 01

Input

1 1 1
1

Output

0

直接附上AC代码：

#include <iostream>
#include <cstdio>
#include <string>
#include <cmath>
#include <iomanip>
#include <ctime>
#include <climits>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <queue>
#include <vector>
#include <set>
#include <map>
//#pragma comment(linker, "/STACK:102400000, 102400000")
using namespace std;
typedef unsigned int li;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
const double pi = acos(-1.0);
const double e = exp(1.0);
const double eps = 1e-8;
const int maxn = 100005;
ll ans[maxn];
int n, a, b;

int main()
{
ios::sync_with_stdio(false);
while (~scanf("%d%d%d", &n, &a, &b))
{
for (int i=0; i<n; i++)
scanf("%I64d", &ans[i]);
for (int i=0; i<n-1; i++)
printf("%I64d ", (ans[i]*a)%b/a);
printf("%I64d\n", (ans[n-1]*a)%b/a);
}
return 0;
}