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codeforces #256 A. Rewards

2015-10-01 16:49 218 查看
A. Rewards

time limit per test
1 second

memory limit per test
256 megabytes

input
standard input

output
standard output

Bizon the Champion is called the Champion for a reason.

Bizon the Champion has recently got a present — a new glass cupboard with
n shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has
a1 first prize cups,
a2 second prize cups and
a3 third prize cups. Besides, he has
b1 first prize medals,
b2 second prize medals and
b3 third prize medals.

Naturally, the rewards in the cupboard must look good, that's why Bizon the Champion decided to follow the rules:

any shelf cannot contain both cups and medals at the same time;
no shelf can contain more than five cups;
no shelf can have more than ten medals.

Help Bizon the Champion find out if we can put all the rewards so that all the conditions are fulfilled.

Input
The first line contains integers a1,
a2 and
a3 (0 ≤ a1, a2, a3 ≤ 100). The second line contains integers
b1,
b2 and b3
(0 ≤ b1, b2, b3 ≤ 100). The third line contains integer
n (1 ≤ n ≤ 100).

The numbers in the lines are separated by single spaces.

Output
Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes).

Sample test(s)

Input
1 1 1
1 1 1
4


Output
YES


Input
1 1 3
2 3 4
2


Output
YES


Input
1 0 0
1 0 0
1


Output
NO
水题不解释
#include <iostream>
using namespace std;
int main()
{
int n,a1,a2,a3,b1,b2,b3;
cin>>a1>>a2>>a3>>b1>>b2>>b3>>n;
if(n>=(a1+a2+a3+4)/5+(b1+b2+b3+9)/10)
cout<<"YES";
else
cout<<"NO";

}


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