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BFS HDOJ 1242 Rescue

2015-09-25 09:46 417 查看
题目传送门

题意:从r走到a,遇到x多走一步,问最小走到a的步数

分析:因为r有多个,反过来想从a走到某个r的最小步数,简单的BFS。我对这题有特殊的感情,去年刚来集训队时肉鸽推荐了这题,当时什么都不会,看个数组模拟队列的BFS看的头晕,现在看起来也不过如此,额,当年开始是从r走到a的,因为数据巨弱才过的,应该要用到优先队列。

/************************************************
* Author        :Running_Time
* Created Time  :2015/9/25 星期五 09:13:51
* File Name     :B_BFS.cpp
************************************************/

#include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std;

#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int N = 2e2 + 10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
const double EPS = 1e-8;
struct Angle    {
int x, y, step;
Angle () {}
Angle (int x, int y, int step) : x (x), y (y), step (step) {}
};
int dx[4] = {-1, 1, 0, 0};
int dy[4] = {0, 0, -1, 1};
bool vis

;
char maze

;
int n, m;

bool judge(int x, int y)    {
if (x < 1 || x > n || y < 1 || y > m || vis[x][y] || maze[x][y] == '#') return false;
else    return true;
}

void BFS(Angle s)    {
int ret = INF;
memset (vis, false, sizeof (vis));
queue<Angle> Q; Q.push (s);
vis[s.x][s.y] = true;
while (!Q.empty ()) {
Angle r = Q.front ();   Q.pop ();
for (int i=0; i<4; ++i) {
int tx = r.x + dx[i];
int ty = r.y + dy[i];
if (!judge (tx, ty))  continue;
vis[tx][ty] = true;
if (maze[tx][ty] == 'r')    {
ret = min (ret, r.step + 1);    continue;
}
else if (maze[tx][ty] == 'x')   {
Q.push (Angle (tx, ty, r.step + 2));    continue;
}
else    Q.push (Angle (tx, ty, r.step + 1));
}
}
if (ret == INF) puts ("Poor ANGEL has to stay in the prison all his life.");
else    printf ("%d\n", ret);
}

int main(void)   {
while (scanf ("%d%d", &n, &m) == 2) {
for (int i=1; i<=n; ++i)    {
scanf ("%s", maze[i] + 1);
}
bool find = false;  Angle start;
for (int i=1; i<=n && !find; ++i)    {
for (int j=1; j<=m; ++j)    {
if (maze[i][j] == 'a')  {
start = Angle (i, j, 0);
find = true;    break;
}
}
}
BFS (start);
}

return 0;
}


当年的代码不忍直视。。。

#include<stdio.h>
typedef struct point
{
int x,y,step;
}target;
int N,M,dir[4][2]={0,1,0,-1,1,0,-1,0},ax,ay;
int flag[202][202];
char map[302][302];
target que[40005];
int BFS(target start)
{
int end,top,i;
int min=1000000;
target in,next;
end=top=0;
que[top]=start;
while (top>=end)
{
in=que[end];
end=(end+1);
for (i=0;i<4;i++)
{
next.x=in.x+dir[i][0];
next.y=in.y+dir[i][1];
if (map[next.x][next.y]=='r')
{
if (min>in.step+1)
min=in.step+1;
}
if (next.x>=0&&next.x<N&&next.y>=0&&next.y<M&&map[next.x][next.y]!='#')
{
if (flag[next.x][next.y]>in.step+1)
{
next.step=in.step+1;
if (map[next.x][next.y]=='x')
next.step++;
flag[next.x][next.y]=next.step;
top=(top+1);
que[top]=next;
}
}
}
}
if (min!=1000000)return min;
else
return -1;
}
int main()
{
int i,j,num;
target start;
while (scanf("%d%d",&N,&M)!=EOF)
{
for (i=0;i<N;i++)
{
scanf("%s",map[i]);
for (j=0;j<M;j++)
{
flag[i][j]=1000000;
if (map[i][j]=='a')
{
//map[i][j]='.';
ax=i;
ay=j;
}
}
}
start.x=ax;
start.y=ay;
start.step=0;
//map[ax][ay]='.';
num=BFS(start);
if (num==-1)
printf("Poor ANGEL has to stay in the prison all his life.\n");
else
printf("%d\n",num);
}
return 0;
}


  
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