您的位置:首页 > 其它

Moving Zeros

2015-09-24 06:22 323 查看
Given an array
nums
, write a function to move all
0
's to the end of it while maintaining the relative order of the non-zero elements.

For example, given
nums = [0, 1, 0, 3, 12]
, after calling your function,
nums
should be
[1, 3, 12, 0, 0]
.

Note:

You must do this in-place without making a copy of the array.

Minimize the total number of operations.

Find the first 0, exchange it with the first non-zero number from its right part.

Runtime: 36ms.

class Solution {
public:
void moveZeroes(vector<int>& nums) {
int n = nums.size();
if(n <= 1) return;

int left = 0, right = 0;
while(right < n){
while(nums[left] != 0)
left++; //find the first number equals to 0
right = left + 1;
while(nums[right] == 0) //find the first number doesn't equal to 0
right++;

if(right >= n) return;

swap(nums[left], nums[right]);
left++;
right++;
}
return;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: