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如何搭建ssh项目(基于注解)

2015-09-17 22:21 489 查看
在JavaEE开发中会使用到struts+hibernate+spring框架组合起来搭建web应用程序,在这里讲一下如何搭建ssh项目

第一步,下载jar包,strutshibernatespring

第二步,分别将以上的jar包及mysql驱动jar包及c3p0jar包放到lib目录下,并build path

第三步,配置web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_9" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> 
<display-name>Struts Blank</display-name>

<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>

<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

<!-- needed for ContextLoaderListener -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>

<!-- Bootstraps the root web application context before servlet initialization -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

</web-app>


第四步,配置db.properties

user=root
password=
jdbcUrl=jdbc:mysql:///ssh
driverClass=com.mysql.jdbc.Driver


第五步,新建applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.1.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.1.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.1.xsd"> <!-- 导入资源文件 -->
<context:property-placeholder location="classpath:db.properties"/>
<!-- 配置数据源 -->
<bean id="dataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
p:user="${user}" p:password="${password}" p:jdbcUrl="${jdbcUrl}"
p:driverClass="${driverClass}"/>

<!-- 配置sessionFactory -->
<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"></property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.format_sql">true</prop>
<prop key="hibernate.hbm2ddl.auto">update</prop>
</props>
</property>
<property name="packagesToScan">
<list>
<value>com.dobeyue.ssh.entities</value>
</list>
</property>
</bean>

<!-- 配置事务管理器 -->
<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"></property>
</bean>

<!-- 使用注解配置事务 -->
<tx:annotation-driven transaction-manager="transactionManager"/>

<!-- 配置切面 -->
<aop:aspectj-autoproxy/>

<!-- 配置扫描的包 -->
<context:component-scan base-package="com.dobeyue.ssh"/>

</beans>


第六步,新建struts.xml

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">

<struts>
<package name="default" namespace="/" extends="struts-default">

</package>

</struts>


第七步,新建包com.dobeyue.ssh.entities,新建User 类文件

package com.dobeyue.ssh.entities;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

import org.springframework.stereotype.Component;
@Component
@Table(name="users")
@Entity
public class User {
private Integer id;
private String userName;
@GeneratedValue(strategy=GenerationType.AUTO)
@Id
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
@Column(name="userName",columnDefinition="varchar(255) default 'dobeyue'")
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
}


最后,运行该应用程序,在数据库中生成users表,即为成功
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