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iOS--判断网络是否可用-(本地判断)

2015-09-14 10:16 639 查看
+(NSString *)getNetWorkStates{
UIApplication *app = [UIApplication sharedApplication];
NSArray *children = [[[app valueForKeyPath:@"statusBar"]valueForKeyPath:@"foregroundView"]subviews];
NSString *state = [[NSString alloc]init];
int netType = 0;
//获取到网络返回码
for (id child in children) {
if ([child isKindOfClass:NSClassFromString(@"UIStatusBarDataNetworkItemView")]) {
//获取到状态栏
netType = [[child valueForKeyPath:@"dataNetworkType"]intValue];

switch (netType) {
case 0:
state = @"无网络";
//无网模式
break;
case 1:
state = @"2g";
break;
case 2:
state = @"3g";
break;
case 3:
state = @"4g";
break;
case 5:
{
state = @"wifi";
}
break;
default:
break;
}
}
}
//根据状态选择
return state;
}


使用 playManager :

/**

* 判断是否有网络

*/

+ (BOOL) isOnNetWork
{
if ([[playManager getNetWorkStates] isEqualToString:@"无网络"] ||
[[playManager getNetWorkStates ] isEqualToString:@""]) {
return NO ;
} else {
return YES ;
}
}
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