与数字相关转换（包括英文和汉语拼音）

数字到英文描述的转换

1.给定一个整数，打印该整数的对应的英文描述，例如输入1234，输出“One Thousand，Two Hundred Thirty Four”

解题思路：

#include<iostream>
#include<string>
using namespace std;
string digits[]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
string teens[]={"Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
string tens[]={"Ten","Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty","Ninety"};
string bigs[]={"","Thousand","Million","Billion"};

string numToString100(int number)
{
string str="";
//转换百位的地方
if(number>100)
{
str+=digits[number/100-1]+" Hundred ";
number%=100;
}
//转换十位的地方
if(number>=11 && number<=19)
{
str+=teens[number-11]+" ";
}
else if(number==10 || number>=20)
{
str+=tens[number/10-1]+" ";
number%=10;
}
if(number>=1 && number<=9)
{
str+=digits[number-1]+" ";
}
return str;
}
string numToString(int number)
{
if(number==0)
{
return "Zero";
}
else if(number<0)
{
return "Negative"+numToString(-1*number);
}

int count=0;
string str="";
while(number>0)
{
if(number%1000 != 0)
{
str=numToString100(number%1000)+bigs[count]+" "+str;
}
number/=1000;
count++;
}
return str;
}
int main()
{
int number;
cin>>number;
string result;
result=numToString(number);
cout<<result<<endl;
}

程序运行结果：

2.拼音转换为数字

将中文数字的拼音字符转为最终的数字，每个字拼音的首字母大写，比如:JiuWanJiuQianJiuBaiJiuShiJiu表示九万九千九百九十九，即阿拉伯数字99999.

你当然就得每个数字的汉语拼音，但是还是提示你一下，Ling、Yi、Er、San、Si、Wu、Liu、Qi、Ba、Jiu、Shi、Bai、Qian、Wan。

为了简单起见，我们要处理的数字在万以内，不含负数，十、百、千、万等单位前面一定有数字，如YiShi表示10.

输入：中文数字的拼音字符串

输出：阿拉伯数字

样例输入：SanBaiLingSan

样例输出：303

解题思路：

首先遍历输入的拼音字符串，根据拼音首字母大写其他字母小写的特点，将拼音字符分离出来，再与拼音字符表进行比较，将其转换成数字和对应单位的值

#include<iostream>
#include<string>
#include<cctype>
using namespace std;

string num[14]={"Ling","Yi","Er","San","Si","Wu","Liu","Qi","Ba","Jiu","Shi","Bai","Qian","Wan"};
int getNum(string str)
{
//cout<<str<<endl;
for(int n=0;n<14;n++)
{
if(num
==str)
return n;
}
}
int main()
{
string str,temp;
cin>>str;
int len=str.size();
int result=0,begin=0,flag=0,number;
for(int i=0;i<len;i++)
{

if(begin==0 || islower(str[i]) && i!=len-1)
{
temp.push_back(str[i]);
begin=1;
}
else
{
if(i==len-1)
{
temp.push_back(str[i]);
i++;    //因为后面i要减1，否则会进入死循环
}
number=getNum(temp);
if(number>=0 && number<=9)
{
flag=number;
}
else
{
if(number==10)
result += flag*10;
else if(number==11)
result += flag*100;
else if(number==12)
result +=flag*1000;
else if(number==13)
result=flag*10000;
}
temp.erase();
i--;
begin=0;
}
}
result += flag;
cout<<result<<endl;
}

程序运行结果：