您的位置:首页 > 其它

[Leetcode-263] Ugly Number(丑陋数)

2015-09-05 10:57 483 查看
Write a program to check whether a given number is an ugly number.

Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since it includes another prime factor 7.

Note that 1 is typically treated as an ugly number.

【分析】思路:根据丑陋数的定义,我们将给定数除以2、3、5,直到无法整除,也就是除以2、3、5的余数不再为0时停止。这时如果得到1,说明是所有因子都是2或3或5,如果不是1,则不是丑陋数。

bool isUgly(int num) {

    if(num<=0)
        return 0;

    int rem2 = num % 2;
    int rem3 = num % 3;
    int rem5 = num % 5;

    while(rem2 == 0 || rem3 == 0 || rem5 == 0) {
        if(rem2 == 0) {
            num = num / 2;
        } else if(rem3 == 0) {
            num = num / 3;
        } else {
            num = num / 5;
        }
        rem2 = num % 2;
        rem3 = num % 3;
        rem5 = num % 5;
    }
    return num == 1;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: