zzuli OJ 1039: n个数求和

Description

Input

Output

Sample Input

Sample Output

HINT

...

Source

#include<stdio.h>

int main()
{
    int i, n;
    int number, sum;

    scanf("%d", &n);
    sum = 0;

    for(i = 1; i <= n; i++) //循环n次，每次读入一个数并累加
    {
        scanf("%d", &number);
        sum += number;
    }

    printf("%d\n", sum);
    return 0;
}