在一个字符串中找到第一个只出现一次的字符

//如输入 abaccdeff，则输出 b
void PrintFirstOneAppearOnce(char* strString)
{
int   nTime[26];
memset(nTime, 0, sizeof(nTime));
for (int i = 0; i < strlen(strString); i++)
{
int nNumber = strString[i] - 'a';
nTime[nNumber] ++;
}

for (int i = 0; i < strlen(strString); i++)
{
int nNumber = strString[i] - 'a';
if(nTime[nNumber] == 1)
{
cout << "result:" << strString[i] << endl;
return;
}
}
cout << "result:not find" << endl;
}