Leetcode: Intersection of Two Linked Lists
2015-08-27 02:37
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Question
Write a program to find the node at which the intersection of two singly linked lists begins.For example, the following two linked lists:
A: a1 → a2
↘
c1 → c2 → c3
↗
B: b1 → b2 → b3
begin to intersect at node c1.
Notes:
If the two linked lists have no intersection at all, return null.
The linked lists must retain their original structure after the function returns.
You may assume there are no cycles anywhere in the entire linked structure.
Your code should preferably run in O(n) time and use only O(1) memory.
Credits:
Special thanks to @stellari for adding this problem and creating all test cases.
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Solution
[code]# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def getIntersectionNode(self, headA, headB): """ :type head1, head1: ListNode :rtype: ListNode """ len1 = self.getlength(headA) len2 = self.getlength(headB) n = abs(len1-len2) if len1<len2: for dummy in range(n): headB = headB.next else: for dummy in range(n): headA = headA.next while headA!=headB: headA, headB = headA.next, headB.next return headA def getlength(self,head): res = 0 while head!=None: res += 1 head = head.next return res
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