LeetCode题解：Reverse Bits

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

题意：逆转32位二进制数的顺序

解决思路：通过与1进行与运算得到最低位数，右移去掉已运算部分，左移进位

代码：

public class Solution {
    // you need treat n as an unsigned value
    public int reverseBits(int n) {
        int result = 0;

        for(int i = 0;i < 32;++i){
            result += (n & 1);
            n >>= 1;
            if(i < 31){
                result <<= 1;
            }
        }

        return result;
    }
}