[LeedCode OJ]#9 Palindrome Number

class Solution
{
public:
    bool isPalindrome(int x)
    {
        if(x>2147483647)
            return false;
        if(x<-2147483648)
            return false;
        long long c = x;
        if(c<0)
        {
            return false;
        }
        long long a = 0,b = c;
        while(c)
        {
            a = a*10+c%10;
            c/=10;
        }
        return a==b;
    }
};