poj 2503 哈希 Map 字典树

Babelfish

Time Limit: 3000MS		Memory Limit: 65536K
Total Submissions: 36967		Accepted: 15749

Description
You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.
Input
Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language
word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.
Output
Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".
Sample Input

dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay

atcay
ittenkay
oopslay

Sample Output

cat
eh
loops

Hint
Huge input and output,scanf and printf are recommended.
Source

//16096K 2625MS
#include<iostream>
#include<cstdio>
#include<map>
#include<cstring>

using namespace std;

int main()
{
char s[100],s1[11];
string ss;
char c;
map<string,string>Q;
int num;
while(gets(s)&&s[0]!='\0')  //读串比读多个字符快
{
int len=strlen(s);
int i;
for( i=0;i<len;i++)
{
if(s[i]==' ')
{s[i]='\0';
break;
}
}
ss=s+i+1;
Q[ss]=s;
}
while(~scanf("%s",s1))
{
if(Q[s1].size())
cout<<Q[s1]<<endl;
else
printf("eh\n");
}
}
//	while(~scanf("%c",&c))  // 超时
//	{
//		if(c=='\n')
//			break;
//		num=0;
//		while(c!=' ')
//		{
//			s[num++]=c;
//			scanf("%c",&c);
//		}
//		s[num]='\0';   //够成字符串
//		num=0;
//		scanf("%c",&c);  //防止上一个空格被读入
//
//		while(c!='\n')
//		{
//			ss[num++]=c;
//			scanf("%c",&c);
//		}
//		ss[num]='\0';
//		Q[ss]=s;
//	}

//字典树 26240K    <span id="transmark"></span>735MS
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cstdlib>

using namespace std;

char ss[100],s[100],c[100010][100];
int num=0;
struct node
{
int flag;
node *next[26];
}*head;
node * Creat()
{
node *p;
p=new node;
p->flag=0;
for(int i=0;i<26;i++)
p->next[i]=NULL;
return p;
}
int Build_Tree()
{
node *p=head;
int len=strlen(s);
for(int i=0;i<len;i++)
{
int a=s[i]-'a';
if(!p->next[a])
{
p->next[a]=Creat();
//p->next[a]->flag=num;
}
p=p->next[a];
}
p->flag=num;
}
int Find(char s1[])
{
int len=strlen(s1);
node *p=head;
for(int i=0;i<len;i++)
{
int a=s1[i]-'a';
if(!p->next[a])
{
return 0;
}
p=p->next[a];
}
return p->flag;
}
int main()
{
num=1;
head=Creat();
while(gets(ss)&&ss[0]!='\0')
{
sscanf(ss,"%s %s",c[num],s);
Build_Tree();
num++;
}
char s1[100];
while(~scanf("%s",s1))
{
int flag=Find(s1);
//cout<<flag;
if(flag)
printf("%s\n",c[flag]);
else
printf("eh\n");
}
}