1092. To Buy or Not to Buy (20)

1092. To Buy or Not to Buy (20)
时间限制100 ms
内存限制65536 kB
代码长度限制16000 B
判题程序Standard作者CHEN, Yue
Eva would like to make a string of beads with her favorite colors so she went to a small shop to buy some beads. There were many colorful strings of beads. However the owner of the shop would only sell the strings in whole pieces. Hence Eva must check whether a string in the shop contains all the beads she needs. She now comes to you for help: if the answer is "Yes", please tell her the number of extra beads she has to buy; or if the answer is "No", please tell her the number of beads missing from the string.For the sake of simplicity, let's use the characters in the ranges [0-9], [a-z], and [A-Z] to represent the colors. For example, the 3rd string in Figure 1 is the one that Eva would like to make. Then the 1st string is okay since it contains all the necessary beads with 8 extra ones; yet the 2nd one is not since there is no black bead and one less red bead.


Figure 1Input Specification:Each input file contains one test case. Each case gives in two lines the strings of no more than 1000 beads which belong to the shop owner and Eva, respectively.Output Specification:For each test case, print your answer in one line. If the answer is "Yes", then also output the number of extra beads Eva has to buy; or if the answer is "No", then also output the number of beads missing from the string. There must be exactly 1 space between the answer and the number.Sample Input 1:ppRYYGrrYBR2258
YrR8RrY

Yes 8

ppRYYGrrYB225
YrR8RrY

No 2

第一串商店的

第二串要买的

问如果买商店的这出串，是否满足要买的颜色和对应的个数：满足，Yes，并给出多买个个数

不满足，No，并给出还差几颗

统计个数的时候是某【颜色需要的个数】和【商店提供的这个颜色个数】取最小

评测结果

测试点

#include<iostream> #include<string>  using namespace std; void countnum(int *c, string a){  int index = 0;   while (a[index]!='\0')  {    if (isdigit(a[index]))       c[a[index] - '0']++;     else if (isupper(a[index]))       c[a[index] - 'A' + 36]++;     else c[a[index] - 'a' + 10]++;     index++;  }}int main(){  string shop, eva;   int count[2][63] = {0};  getline(cin, shop);  getline(cin, eva);  countnum(count[0],eva);    countnum(count[1],shop);  int goal = 0;  int index = 0;  while (index < 63)  {    if (count[0][index] != 0 )      goal += count[0][index] <= count[1][index] ? count[0][index] : count[1][index];    index++;  }   if (goal < eva.size())     cout << "No " << eva.size() - goal << endl;   else     cout << "Yes " << shop.size() - goal << endl;   system("pause");  return 0;}