[TOJ 3655] Bomb

The counter-terrorists found a time bomb in the dust. But this time the terrorists improve on the time bomb. The number sequence of the time bomb counts from 1 to N. If the current number sequence includes the sub-sequence "49", the power of the blast would
add one point.

Now the counter-terrorist knows the number N. They want to know the final points of the power. Can you help them?

Input

The first line of input consists of an integer T (1 <= T <= 10000), indicating the number of test cases. For each test case, there will be an integer N (1 <= N <= 2^63-1) as the description.

The input terminates by end of file marker.

Output

For each test case, output an integer indicating the final points of the power.

Sample Input

3
1
50
500

Sample Output

0
1
15

很简单的数位统计题， 此类题目最好一律采用记忆化搜索的方法进行统计，好想又好写。

#include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
long long dp[100][3];
long long n;
int num[100];
long long dfs(int pos,int have,int ca)
{
    if(pos==-1) return have==2;
    if(!ca&&dp[pos][have]!=-1) return dp[pos][have];
    int v=ca?(num[pos]):9;
    long long ans=0;
    for(int i=0;i<=v;i++)
    {
        int nhave=have;
        if(have==0&&i==4)
            nhave=1;
        if(have==1&&i!=4)
            nhave=0;
        if(have==1&&i==9)
            nhave=2;
        ans+=dfs(pos-1,nhave,ca&&(i==v));
    }
    if(!ca)
    {
        return dp[pos][have]=ans;
    }
    return ans;

}
long long get(long long p)
{
    int len=0;
    while(p)
    {
        num[len++]=p%10;
        p/=10;
    }
    return dfs(len-1,0,1);
}
int main()
{
    memset(dp,-1,sizeof(dp));
    int t;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%lld",&n);
        printf("%lld\n",get(n));
    }
}