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zoj 2859 二维线段树 插点求线

2015-08-18 10:22 477 查看
题意:….

思路:二维线段树。。 理解好Modify操作

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;
const int maxn = 320;
const int INF = 0x3ff3f3f;
int locy[maxn],locx[maxn];
struct nodey
{
int l, r;
int Max,Min;
};
int n,b,k;
struct nodex
{
int l,r;
nodey sty[maxn*4];
void build(int i, int _l, int _r)
{
sty[i].l = _l;
sty[i].r = _r;
sty[i].Max = -INF;
sty[i].Min = INF;
if(_l == _r)
{
locy[_l] = i;
return;
}
int mid = (_l+_r)/2;
build(i<<1, _l, mid);
build(i<<1|1, mid+1, _r);
}
int queryMin(int i, int _l, int _r)
{
if(sty[i].l == _l && sty[i].r == _r)
return sty[i].Min;
int mid = (sty[i].l + sty[i].r)/2;
if(_r<=mid) return queryMin(i<<1, _l, _r);
else if(_l>mid) return queryMin(i<<1|1, _l, _r);
else
{
int t1 = queryMin(i<<1, _l, mid);
int t2 = queryMin(i<<1|1, mid+1, _r);
return min(t1,t2);
}
}
int queryMax(int i, int _l, int _r)
{
if(sty[i].l == _l && sty[i].r == _r)
return sty[i].Max;
int mid = (sty[i].l + sty[i].r)>>1;
if(_r<=mid) return queryMax(i<<1, _l, _r);
else if(_l>mid) return queryMax(i<<1|1, _l, _r);
else
{
int t1 = queryMax(i<<1, _l, mid);
int t2 = queryMax(i<<1|1, mid+1, _r);
return max(t1, t2);
}
}
}stx[maxn*4];
void build(int rt, int _l, int _r)
{
stx[rt].l = _l;
stx[rt].r = _r;
stx[rt].build(1, 1, n);
if(_l == _r)
{
locx[_l] = rt;
return;
}
int mid = (_l + _r)>>1;
build(rt<<1, _l, mid);
build(rt<<1|1, mid+1, _r);
}
int queryMin(int i, int x1, int y1, int x2, int y2)
{
if(stx[i].l == x1&&stx[i].r == x2)
return stx[i].queryMin(1, y1, y2);
int mid = (stx[i].l+stx[i].r)>>1;
if(x2<=mid) return queryMin(i<<1, x1, y1, x2, y2);
else if(x1>mid) return queryMin(i<<1|1, x1, y1, x2, y2);
else
{
int a = queryMin(i<<1, x1, y1, mid, y2);
int b = queryMin(i<<1|1, mid+1, y1, x2, y2);
return min(a, b);
}
}
int  queryMax(int i, int x1, int y1, int x2, int y2)
{
if(stx[i].l == x1&&stx[i].r == x2)
return stx[i].queryMax(1, y1, y2);
int mid = (stx[i].l+stx[i].r)>>1;
if(x2<=mid) return queryMax(i<<1, x1, y1, x2, y2);
else if(x1>mid) return queryMax(i<<1|1, x1, y1, x2, y2);
else
{
int a = queryMax(i<<1, x1, y1, mid, y2);
int b = queryMax(i<<1|1, mid+1, y1, x2, y2);
return max(a, b);
}
}
void Modify(int x, int y, int val)
{
int tx = locx[x];
int ty = locy[y];
stx[tx].sty[ty].Min = stx[tx].sty[ty].Max = val;
for(int i=tx;i;i>>=1)
for(int j=ty; j; j>>=1)
{
if(i == tx&& j == ty) continue;
if(j == ty)
{
stx[i].sty[j].Min = min(stx[i<<1].sty[j].Min, stx[i<<1|1].sty[j].Min);
stx[i].sty[j].Max = max(stx[i<<1].sty[j].Max, stx[i<<1|1].sty[j].Max);
}
else
{
stx[i].sty[j].Min = min(stx[i].sty[j<<1].Min,stx[i].sty[(j<<1)|1].Min);
stx[i].sty[j].Max = max(stx[i].sty[j<<1].Max,stx[i].sty[(j<<1)|1].Max);
}
}
}

int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
int T;
scanf("%d",&T);
int iCase = 0;
while(T--)
{
iCase++;
scanf("%d",&n);
build(1,1,n);
for(int i = 1;i <= n;i++)
for(int j = 1;j <= n;j++)
{
int a;
scanf("%d",&a);
Modify(i,j,a);
}
int q;
int x1,y1,x2,y2;
scanf("%d",&q);
while(q--)
{
scanf("%d%d%d%d",&x1,&y1,&x2, &y2);
int Min = queryMin(1,x1,y1,x2,y2);
printf("%d\n",Min);
}
}
return 0;
}
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标签:  线段树