浙江大学PAT_甲级_1015. Reversible Primes (20)
2015-08-17 06:52
423 查看
题目链接:点击打开链接
A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime.
Now given any two positive integers N (< 105) and D (1 < D <= 10), you are supposed to tell if N is a reversible prime with radix D.
Input Specification:
The input file consists of several test cases. Each case occupies a line which contains two integers N and D. The input is finished by a negative N.
Output Specification:
For each test case, print in one line "Yes" if N is a reversible prime with radix D, or "No" if not.
Sample Input:
Sample Output:
我的Java代码:
A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime.
Now given any two positive integers N (< 105) and D (1 < D <= 10), you are supposed to tell if N is a reversible prime with radix D.
Input Specification:
The input file consists of several test cases. Each case occupies a line which contains two integers N and D. The input is finished by a negative N.
Output Specification:
For each test case, print in one line "Yes" if N is a reversible prime with radix D, or "No" if not.
Sample Input:
73 10 23 2 23 10 -2
Sample Output:
Yes Yes No
我的Java代码:
import java.util.*; import java.math.*; import static java.lang.System.*; public class Main { public boolean IsPrime(int value)//判断素数方法 { int i = 2; if (value == 0 || value == 1) return false; for (i=2; i <=Math.sqrt(value); i++) { if (value%i == 0) return false; } return true; } public int reverse(int num,int d)//将10进制数字转换为d进制,并翻转,再转换为10进制 { int sum=0; do { sum=sum*d+num%d; num=num/d; }while(num!=0); return sum; } public static void main(String[] args) { Scanner cin=new Scanner(in); Main m=new Main(); int num=0,d=1;//num输入的数字,d进制 while(cin.hasNextInt()) { num=cin.nextInt(); if(num<0)//输入负数结束 break; d=cin.nextInt(); if(m.IsPrime(num)&&m.IsPrime(m.reverse(num, d)))//num是质数,且翻转后还是质数 { out.println("Yes"); } else { out.println("No"); } } } }
相关文章推荐
- 第58讲:Scala中Abstract Types实战详解
- Ogre+Havok研究------一、框架搭建
- Confuse about hkQuaternion and hkRotation
- GPIO Interfaces
- 寻找志同道合的伙伴
- WeakReference与SoftReference
- CODEVS 1069关押罪犯
- CODEVS 1067 机器翻译
- jQuery基础----24jQuery扩展-noConflict
- jQuery基础----23jQuery扩展-jQuery扩展
- jQuery基础----22jQuery AJAX-加载片段
- java finalize方法
- jQuery基础----21jQuery AJAX-异步访问
- PS------裁剪工具的使用
- 用NAN简化Google V8 JS引擎的扩展
- 用NAN简化Google V8 JS引擎的扩展
- 【Django】上传图片之路径问题
- 关于Win 10的隐私保护政策
- C++容器vector的调用
- codeforces 520 B. Two Buttons (bfs)