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MAVEN下实现spring boot打包成war包(spring boot 01)

2015-08-03 22:08 721 查看

配置类(带有@SpringBootApplication)继承SpringBootServletInitializer,同时重写configure方法

e.g:
@SpringBootApplication
public class Application extends SpringBootServletInitializer {

@Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
return application.sources(Application.class);
}

public static void main(String[] args) throws Exception {
SpringApplication.run(Application.class, args);
}

}


修改pom.xml中package

<packaging>jar</packaging> --> <packaging>war</packaging>


标记嵌入的容器dependencies as “provided”

e.g:
<dependencies>
<!-- ... -->
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-tomcat</artifactId>
<scope>provided</scope>
</dependency>
<!-- ... -->
</dependencies>


Create a deployable war file for older servlet containers

Older Servlet containers don’t have support for the ServletContextInitializer bootstrap process used in Servlet 3.0. You can still use Spring and Spring Boot in these containers but you are going to need to add a web.xml to your application and configure it to load an ApplicationContext via a DispatcherServlet.

Spring 同时提醒我们,如果是比较早的servlet容器(低于Servlet 3.0),可能不支持ServletContextInitializer,这时我们需要给项目配置一个web.xml,并将配置类加载进项目。以下是spring官方给出的方案:

Deploying a WAR in an Old (Servlet 2.5) Container

Spring Boot uses Servlet 3.0 APIs to initialize the ServletContext (register Servlets etc.) so you can’t use the same application out of the box in a Servlet 2.5 container. It is however possible to run a Spring Boot application on an older container with some special tools. If you include org.springframework.boot:spring-boot-legacy as a dependency (maintained separately to the core of Spring Boot and currently available at 1.0.0.RELEASE), all you should need to do is create a web.xml and declare a context listener to create the application context and your filters and servlets. The context listener is a special purpose one for Spring Boot, but the rest of it is normal for a Spring application in Servlet 2.5.

e.g:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> 
<context-param>
<param-name>contextConfigLocation</param-name>
<!-- demo.Application即为被标注@SpringBootApplication的类 -->
<param-value>demo.Application</param-value>
</context-param>

<listener>
<!-- 添加监听SpringBootContextLoaderListener -->
<listener-class>org.springframework.boot.legacy.context.web.SpringBootContextLoaderListener</listener-class>
</listener>

<filter>
<filter-name>metricFilter</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
<filter-name>metricFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextAttribute</param-name>
<param-value>org.springframework.web.context.WebApplicationContext.ROOT</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>


@see more

http://spring.io/guides/gs/convert-jar-to-war/

http://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#build-tool-plugins-maven-packaging

http://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#howto-create-a-deployable-war-file

http://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#howto-servlet-2-5
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