leetcode刷题目 总结 记录 备忘11

leetcode11

Container With Most Water

Given n non-negative integers a1, a2,
..., an, where each represents a point at coordinate (i, ai). n vertical
lines are drawn such that the two endpoints of line i is at (i, ai) and (i,
0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.
从两头开始 ，先求一次面积，两边下标差乘两者之间的最低值，即短板，之后开始遍历，数值小的一方往里走，因为是短板，所以得自己往里走，以期能找到一个让对面的数值成为小值的数，才有可能取得最大的面积，之后继续计算面积，与之前的面积相比，替换小的，完成遍历即可。原谅我的语言表述能力较弱。

class Solution {
public:
    int maxArea(vector<int>& height) {
        int l = 0, r = height.size() - 1;
        int max = 0;
        
        while (l < r)
        {
            int temp = (r-l) * min(height[l], height[r]);
            if (temp > max)
            max = temp;
            
            if (height[l] <= height[r])
            l++;
            else
            r--;
        }
        
        return max;
    }
};