poj 2187 凸包or旋转qia壳法
2015-07-29 19:26
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题意:
给n(50000)个点,求这些点与点之间距离最大的距离。
解析:
先求凸包然后暴力。
或者旋转卡壳大法。
代码:
给n(50000)个点,求这些点与点之间距离最大的距离。
解析:
先求凸包然后暴力。
或者旋转卡壳大法。
代码:
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cstring> #include <cmath> #include <stack> #include <vector> #include <queue> #include <map> #include <climits> #include <cassert> #define LL long long using namespace std; const int inf = 0x3f3f3f3f; const double eps = 1e-8; const double pi = acos(-1.0); const double ee = exp(1.0); ///////////////////////////////////////////////////// struct Point { double x, y; Point(double x = 0, double y = 0) : x(x), y(y) {} }; bool cmp(Point A, Point B) { if (A.x == B.x) return A.y < B.y; return A.x < B.x; } typedef Point Vector; Vector operator + (Vector A, Vector B) { return Vector(A.x + B.x, A.y + B.y); } Vector operator - (Point A, Point B) { return Vector(A.x - B.x, A.y - B.y); } Vector operator * (Vector A, double p) { return Vector(A.x * p, A.y * p); } Vector operator / (Vector A, double p) { return Vector(A.x / p, A.y / p); } //便于点排序 bool operator < (const Point& a, const Point& b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } //用于判断相等 int dcmp(double x) { if (fabs(x) < eps) { return 0; } else { return x < 0 ? -1 : 1; } } bool operator == (const Point& a, const Point& b) { return dcmp(a.x - b.x) == 0 && dcmp(a.y - b.y) == 0; } //点积 double Dot(Vector A, Vector B) { return A.x * B.x + A.y * B.y; } //向量长度 double Length(Vector A) { return sqrt(Dot(A, A)); } //向量夹角 double Angle(Vector A, Vector B) { return acos(Dot(A, B) / Length(A) / Length(B)); } //叉集 double Cross(Vector A, Vector B) { return A.x * B.y - A.y * B.x; } //求两个向量相夹的面积 double Area2(Point A, Point B, Point C) { return Cross(B - A, C - A); } //旋转rad弧度 Vector Rotate(Vector A, double rad) { return Vector(A.x * cos(rad) - A.y * sin(rad), A.x * sin(rad) + A.y * cos(rad)); } //向量的单位法线即向量左转90° Vector Normal(Vector A) { double L = Length(A); return Vector(-A.y / L, A.x / L); } //求交点坐标 Point GetLineIntersection(Point P, Vector v, Point Q, Vector w) { Vector u = P - Q; double t = Cross(w, u) / Cross(v, w); return P + v * t; } //点P到直线AB的距离 double DistanceToLine(Point P, Point A, Point B) { Vector v1 = B - A; Vector v2 = P - A; return fabs(Cross(v1, v2)) / Length(v1); } //点到直线的距离 double DistanceToSegment(Point P, Point A, Point B) { if (A == B) { return Length(P - A); } Vector v1 = B - A; Vector v2 = P - A; Vector v3 = P - B; if (dcmp(Dot(v1, v2)) < 0) return Length(v2); else if (dcmp(Dot(v1, v3)) > 0) return Length(v3); else return fabs(Cross(v1, v2)) / Length(v1); } //判断线段是否相交 bool SegmentProperIntersection(Point a1, Point a2, Point b1, Point b2) { double c1 = Cross(a2 - a1, b1 - a1), c2 = Cross(a2 - a1, b2 - a1); double c3 = Cross(b2 - b1, a1 - b1), c4 = Cross(b2 - b1, a2 - b1); return dcmp(c1) * dcmp(c2) < 0 && dcmp(c3) * dcmp(c4) < 0; } //线段是否在端点相交 + 线段相交的判定 bool OnSegment(Point p, Point a1, Point a2) { return dcmp(Cross(a1 - p, a2 - p)) == 0 && dcmp(Dot(a1 - p, a2 - p)) < 0; } //传入顶点集 计算多边形的面积 double ConvexPolygonArea(Point* p, int n) { double area = 0; for (int i = 1; i < n - 1; i++) { area += Cross(p[i] - p[0], p[i + 1] - p[0]); } return area / 2.0; } //° -> 弧度 double torad(double deg) { return deg / 180 * pi; } //求凸包 返回点个数 ch为凸包的点 int ConvexHull(Point* p, int n, Point* ch) { sort(p, p + n); int m = 0; for (int i = 0; i < n; i++) { while (m > 1 && Cross(ch[m - 1] - ch[m - 2], p[i] - ch[m - 2]) <= 0) m--; ch[m++] = p[i]; } int k = m; for (int i = n - 2; i >= 0; i--) { while (m > k && Cross(ch[m - 1] - ch[m - 2], p[i] - ch[m - 2]) <= 0) m--; ch[m++] = p[i]; } if (n > 1) m--; return m; } Point readPoint() { double x, y; scanf("%lf %lf", &x, &y); return Point(x, y); } ////////////////////////////////////////////////////// const int maxn = 50000 + 10; int n; Point p[maxn << 1]; Point ch[maxn << 1]; double dist(Point a, Point b) { return Dot(a - b, a - b); } void bruteForce() { double ans = 0; int m = ConvexHull(p, n, ch); for (int i = 0; i < m; i++) { for (int j = i + 1; j < m; j++) { ans = max(ans, dist(ch[i], ch[j])); } } printf("%.0lf\n", ans); } void rotatingCalipers() { double ans = 0; int m = ConvexHull(p, n, ch); if (m == 2) { printf("%.0lf\n", dist(ch[0], ch[1])); return; } int i = 0, j = 0; for (int k = 0; k < m; k++) { if (ch[k] < ch[i]) i = k; if (ch[j] < ch[k]) j = k; } int si = i, sj = j; while (i != sj || j != si) { ans = max(ans, dist(ch[i], ch[j])); if (Cross(ch[(i + 1) % m] - ch[i], ch[(j + 1) % m] - ch[j]) < 0) { i = (i + 1) % m; } else { j = (j + 1) % m; } } printf("%.0lf\n", ans); } int main() { #ifdef LOCAL freopen("in.txt", "r", stdin); #endif // LOCAL while (~scanf("%d", &n)) { for (int i = 0; i < n; i++) { p[i] = readPoint(); } rotatingCalipers(); } return 0; }
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