Leetcode Q136: Single Number
2015-07-28 22:22
253 查看
题目136：
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
/* 对数组全部元素进行异或操作，相同元素异或结果为0，结果即为单个的数 */
int singleNumber(int* nums, int numsSize)
{
int res = nums[0];
int i = 0;
for(i = 1; i < numsSize; i++)
{
res ^= nums[i];
}
return res;
}
内容来自用户分享和网络整理，不保证内容的准确性，如有侵权内容，可联系管理员处理 
相关文章推荐
- leetcode 179 Largest Number
- leetcode 24 Swap Nodes in Pairs
- leetcode 2 Add Two Numbers 方法1
- leetcode 2 Add Two Numbers 方法2
- [LeetCode]47 Permutations II
- [LeetCode]65 Valid Number
- [LeetCode]123 Best Time to Buy and Sell Stock III
- [LeetCode] String Reorder Distance Apart
- [LeetCode] Sliding Window Maximum
- [LeetCode] Find the k-th Smallest Element in the Union of Two Sorted Arrays
- [LeetCode] Determine If Two Rectangles Overlap
- [LeetCode] A Distance Maximizing Problem
- leetcode_linearList
- leetcode_linearList02
- LeetCode[Day 1] Two Sum 题解
- LeetCode[Day 2] Median of Two Sorted Arrays 题解
- LeetCode[Day 3] Longest Substring Without... 题解
- LeetCode [Day 4] Add Two Numbers 题解
- LeetCode [Day 5] Longest Palindromic Substring 题解
- LeetCode [Day 6] ZigZag Conversion 题解