判断未来是星期几

#include <iostream>

using namespace std;

int main()

{

int day,dotay;

cout<<" Today is (填一个数字)";

cin>>dotay;

cout<<endl;

cout<<"day is : ";

cin>>day;

switch((day+dotay)%7)

{

case 0 :

cout<<" Future is Sunday !"<<endl;

break;

case 1 :

cout<<" Future is Monday !"<<endl;

break;

case 2 :

cout<<" Future is Tuesday !"<<endl;

break;

case 3 :

cout<<" Future is Wednesday !"<<endl;

break;

case 4 :

cout<<" Future is Thursday !"<<endl;

break;

case 5 :

cout<<" Future is Friday !"<<endl;

break;

case 6 :

cout<<" Future is Saturday !"<<endl;

break;

default :

cout<<" Day out of range Monday to Sunday !"<<endl;

break;

}

return 0;

}