[Leetcode 81, Medium] Search in Rotated Sorted Array II

Problem:

Follow up for "Search in Rotated Sorted Array":

What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.
Analysis:

Solutions:

C++:

bool search(vector<int> A, int target) 
    {
        int n = A.size();
        if(n == 0)
            return false;
            
        for(int start = 0, end = n -1; start <= end;) {
            for(;start < end && A[start + 1] == A[start];)
                ++start;
            for(; end > start && A[end - 1] == A[end];)
                --end;
                
            if(A[start] == target)
                return true;
            else if(A[end] == target)
                return true;

            if(start >= end - 1)
                break;

            int mid = (start + end) / 2;
            if(A[mid] == target)
                return true;
            else if(A[mid] >= A[start] && A[mid] >= A[end]) {
                for(;mid >= start && A[mid - 1] == A[mid];)
                    --mid;
                if(target > A[start] && target < A[mid])
                    end = mid;
                else
                    start = mid;
            } else {
                for(;mid <= end && A[mid + 1] == A[mid];)
                    ++mid;
                if(target > A[mid] && target < A[end])
                    start = mid;
                else
                    end = mid;
            }
        }

        return false;
    }

Java:

Python: