《C程序设计语言》学习笔记——练习2-4

/*
练习2-4 重写squeeze(s1,s2)函数，把字符串s1与字符串s2中字符匹配的各个字符都删除掉。
*/
#include <stdio.h>
#define MAX 50

void squeeze(char s1[], char s2[])
{
int i, j, index; /* j指示s1中删除多余字符后应存储下一个字符的正确位置 */
for (index = 0; s2[index] != '\0'; ++index)
{
for (i = j = 0; s1[i] != '\0'; ++i)
if (s1[i] != s2[index])
s1[j++] = s1[i];
s1[j] = '\0'; /* 修改s1正确的结束位置 */
}
}

main()
{
char s1[MAX], s2[MAX];
printf("input s1:");
scanf("%s", s1);
printf("input s2:");
scanf("%s", s2);
squeeze(s1, s2);
printf("\ns1:%s\n", s1);
}