HDU 1061 Rightmost Digit

Problem Description

Given a positive integer N, you should output the most right digit of N^N.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case contains a single positive integer N(1<=N<=1,000,000,000).

Output

For each test case, you should output the rightmost digit of N^N.

Sample Input

2
3
4

Sample Output

7
6

Hint

In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.

In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.

快速幂

#include<cstdio>
#include<queue>
#include<stack>
#include<cstring>
#include<vector>
#include<map>
#include<iostream>
#include<algorithm>
#include<functional>
using namespace std;

int main()
{
    int n,T;
    cin>>T;
  while (T--)
  {
      cin>>n;
      int i,j,k;
      for (i=n,j=n%10,k=1;i;i>>=1)
      {
          if (i&1) k=k*j%10;
          j=j*j%10;
      }
      cout<<k<<endl;
  }
  return 0;
}