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求二叉树深度和copy二叉树

2015-07-18 22:02 351 查看
// operatorTree.cpp
// 对树的操作

#include <iostream>
#include <cstdio>

// 二叉树表示法
typedef struct BiTNode
{
int	data;
struct BiTNode *lchild, *rchild;
}BiTNode, *BiTree;

// 中序遍历
void inOrder(BiTNode *T)
{
if (T == NULL) {
return;
}

inOrder(T->lchild);

printf("%d ", T->data);

inOrder(T->rchild);
}

// 计算树的高度
int depthTree(BiTNode *T)
{
if (!T) {
return 0;
}

int depthVal = 0;
int depthLeft = 0, depthRight = 0;

depthLeft = depthTree(T->lchild);
depthRight = depthTree(T->rchild);

depthVal = 1 + (depthLeft > depthRight ? depthLeft : depthRight);
return depthVal;
}

// copy二叉树
BiTNode* copyTree(BiTNode *T)
{
if (T == NULL) {
return NULL;
}

BiTNode *newNode = (BiTNode *)malloc(sizeof(BiTNode));
if (newNode == NULL) {
free(newNode);
return NULL;
}
newNode->data = T->data;
newNode->lchild = copyTree(T->lchild);
newNode->rchild = copyTree(T->rchild);

return newNode;
}

void operatorTree()
{
BiTNode nodeA, nodeB, nodeC, nodeD, nodeE;

memset(&nodeA, 0, sizeof(BiTNode));
memset(&nodeB, 0, sizeof(BiTNode));
memset(&nodeC, 0, sizeof(BiTNode));
memset(&nodeD, 0, sizeof(BiTNode));
memset(&nodeE, 0, sizeof(BiTNode));

nodeA.data = 1;
nodeB.data = 2;
nodeC.data = 3;
nodeD.data = 4;
nodeE.data = 5;

nodeA.lchild = &nodeB;
nodeA.rchild = &nodeC;
nodeB.lchild = &nodeD;
nodeC.lchild = &nodeE;

int depth = depthTree(&nodeA);
printf("Depth: %d\n", depth);
// Depth: 3

BiTNode *newTree = NULL;
newTree = copyTree(&nodeA);
printf("inorder traversal new tree.\n");
inOrder(&nodeA);
// 4 2 1 5 3
printf("\n");
}

int main()
{
operatorTree();

return 0;
}
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