pat 1001. A+B Format (20)

1001. A+B Format (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input

-1000000 9

Sample Output

-999,991

解：简单的运算，当时考虑的是从左往右每三个一组，有几个测试样例一直不过，正确的做法是从右往左每三个一组，举个例子，如2222，按标准格式输出应该是2,222，而不是222,2。其他的倒是没什么该注意的，数组保存每位的值，输出控制下即可。

贴上代码：

#include<iostream>
#include<cmath>
#include<cstdlib>
#include<cstring>
#include<cstdio>
using namespace std;
int main()
{
    int a,b;
    while(scanf("%d%d",&a,&b)==2)
    {
        int c=a+b;
        int flag=0;
        if(c<0) flag=1;
        if(abs(c)/1000)
        {
            int a[10],cnt=0;
            string s;
            memset(a,0,sizeof(a));
            c=abs(c);
            do
            {
                a[cnt++]=c%10;
                c=c/10;
            }while(c);
            if(flag==1)
                cout<<"-";
            int count=0;
            for(int i=cnt-1;i>=0;i--)
            {
                if((i+1)%3==0&&i!=cnt-1)
                        cout<<',';
                count++;
                    cout<<a[i];
            }
            cout<<endl;
        }
        else
        {
            printf("%d\n",c);
        }
    }
    return 0;
}